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Politics : Formerly About Advanced Micro Devices

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To: Yousef who wrote (25198)	10/21/1997 4:07:00 PM
From: Paul Engel	Read Replies (2) of 1574703

Yousef - Performance and Operating Voltage You neglected to discuss a HUGE drawback for a high operating voltages - POWER dissipation. You know this already, but for Petz: Power Dissipation = 1/2 C(V^2)F, C= capacitance, V = operating voltage, F = operating frequency. For "equivalent" processes (Ca = Ci), Pa/Pi = Va^2/Vi^2. For AMD, Va = 2.5 For Intel, Vi = 1.8 Therefore, Pa/Pi = 1.93 (Assuming equal frequencies) Which implies that AMD's K6 will pump out 93% more heat than Intel's Tillamook at the same frequency. Judging by the reported 8 to 9 watts power dissipation for the K6/0.25 micron at 266 MHz and Intel's 3.5 to 4 watts for the Tillamook at a slightly lower 233 MHz, these calculations are fairly accurate and indicative of AMD's upcoming problems with OEMs! Adjusting the Power dissipation for the Tillamook (233 to 266), Pi = 4 x (266/233) = 4.6 watts. AMD's K6 at 8 or 9 watts is in for some problems. Since AMD has "leaked" that the K6/0.25 micron devcie will operate at 2.1 volts and not 2.5 volts, I predict that the K6/0.25 mciron device will APPEAR at frequencies around 200 and 233 MHz - NOT 266 MHz. Paul

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