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Politics : Formerly About Advanced Micro Devices
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To: Petz who wrote (43702)12/21/1998 2:29:00 AM
From: Kevin K. Spurway   of 1577556
 
Re: "(31400 mm^2 per wafer / 117mm^2) * 90% useful area * 60% typical AMD yield = 145 K6-3 chips per wafer"

The K6-3 is a "squarer" chip than the K6-2, so AMD's number of dice/wafer might not fall as much as you might think--making no assumptions about the accuracy of your initial estimate.

Kevin
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