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Strategies & Market Trends : TA-Quotes Plus

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To: ED_L who wrote (9853)8/17/1999 7:09:00 PM
From: Bob Jagow   of 11149
 
Interesting scan, Ed.
I tend to average three lengths of an indicator a lot because it, as Chande showed
back when, gives the equivalent of an adaptive version on the cheap.
Hadn't thought of using the idea for max, but your
MAXX:= (max(-1,-35,cl)+ max(-1,-25,cl)+ max(-1,-18,cl))/3;
accomplishes that -- it behave more like the 18-day component when
a shorter trend is in place.

Looks like you've tuned it quite a bit already, but you might try relaxing some
of the conditions and sorting on them to see what might improve it.
The one backtest [below] that I ran didn't give any big winners but
these are trying times :o)

Bob
[I pasted the backtest version of your scan below the results.]
----
ACTN,0.04,-30,07/02/1999
NEON,0.10,-30,07/02/1999
ONHN,0.03,-30,07/02/1999
PRGS,0.02,-30,07/02/1999
VMSI,0.00,-30,07/02/1999
--------
//input = "100k.lst";
issuetype common;
daystoload=400;
integer tbar; tbar := -30; /// set here *********
output="Pullback-30.lst";
float AvgC200,AvgC3,AvgC3,MAXX,Slope,UTX;
AvgC200:=MovAvg(tbar,200,CL);
Slope:=(AvgC200 -MovAvg(tbar-2,200,CL))/2;
AvgC3:=MovAvg(tbar,3,CL);
MAXXX := (max(tbar-1,tbar-35,cl)+max(tbar-1,tbar-25,cl)+max(tbar-1,tbar-18,cl))/3;
UTX:= 1.15*AvgC200;

if Close(tbar) > 5 and InstHold > 42 and Slope > 0 and MAXX > 1.15*AvgC200
and Close(tbar) < 0.9*MAXX and AvgC3 > 0.95*AvgC200 and MovAvg(tbar,7,vol) > 145000
and Vol(tbar) > 1.08*Vol(-1) and Low(tbar) > Low(-1)
and MACD(tbar) > MACD(tbar-1) and Low(tbar) < UTX then

println symbol,",",Slope:3:2,",",tbar,",",date(tbar);
endif;
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