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Pastimes : INTERMEDIATE ALGEBRA
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To: Nazbuster who wrote (82)9/19/1999 10:22:00 PM
From: Little Poo  Read Replies (1) of 96
 
the radius, x, of the inner circle is perpendicular
to the tangent chord. so we get a right triangle with
legs 1/2 (half the chord)and x, and hypotenuse r (the
radius of the outer circle. so, x^2+(1/2)^2=r^2.....and
x=sqrt(r^2-1/4). (this requires believing that the inner
circle and outer intersect at the midpoint of the curve.
whaddya think? back to the bills....
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