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Technology Stocks : The New Qualcomm - a S&P500 company
QCOM 165.13+1.1%Nov 26 3:59 PM EST

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To: RalphCramden who wrote (4008)12/7/1999 1:17:00 PM
From: engineer  Read Replies (1) of 13582
 
Mike,

Do the math.

12,500 kHZ divided by 30 kHz divided by Frequncy reuse of 7. You get 59 and change. Add some guardband and you get 57 per sector (best case..). There is no 1.25 MHZ limit on the analog, just 30 kHz channels. So you would just block out about 2.5 channels (rounded up to 3) to get room for HDR. But those 3 channels block out about 80 users in CDMA.

Now take 1.25 Mhz, mulitply by 10 for the useable space of 12.5 Mhz. then take 27 users per sector and then multiply by 3 for 3 sectored cells. Looks like 10*27*3, or close to 900 for a total cell in CDMA.

One other factor that is not quoted often, but the analog system really has alot of problems if you try to stack microcells closer than a certain goegrphical distance, in that the falloff of the signal is R**4 power. If you tried to turn down the power in a cell and limit it's radius to say 1000 meters, you would be very hard pressed to get it right due to the frequency reuse parameters. CDMA does not have this problem so you can have a very good base for frequncy reuse.

NOTE: I am not just doing the math, but relating a couple of years in the field....
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