"That is 1.70 Amps, you nit picking moron"
Nice try, Paul. Do you always stop reading on a
first line that suit your need?
Why don't you take a comparable voltage of 1.4V,
and read "8.04A", which is 45% of 18A in normal
operational mode?
developer.intel.com
(page 26, Table 9)
Senility is showing off, my dear, or what?
Try to follow me: what we are talking about? Leakage,
and transistor quality. How do you compare anything?
At equal conditions, which is at the nominal operating
voltage. Hint: if you drop voltage to zero, the chip
will consume no current. So, what was you point about
0.95V?
- Ali
P.S. Of course, to be accurate, we need to normalize
the AMD data of 0.66A proportionally, i.e. multiply by 1.75/1.35, which stiil gives 0.85A, (<2.5%), or far
cry from Intel 45% leakage sucker. We are talking about
a factor of 20, don't we? |
