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To: AllansAlias who wrote (26823)	1/6/2002 4:25:37 PM
From: Doppler	Read Replies (1) of 209892

My preferred has 1 ending where your a of 2 does. Then my 2 ends where your ii of 3 does. Our 3s end the same but why can't 4 end where your a of 3 does. It would be identical in time to 2 if it ended at a. Then your b of 4 becomes a 5. If so the move off the Sept low becomes the a of an abc with another plunge to come. Is this count feasible and what argues against it. TIA

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