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Pastimes : Clown-Free Zone... sorry, no clowns allowed
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To: benwood who wrote (144663)1/18/2002 1:27:13 PM
From: Oblomov  Read Replies (1) of 436258
 
>>the random odds of going 22 for 22 would be 1 in 4,194,304.

This calculation assumes independent, identically distributed likelihood of change in the components. While the result is amusing, the assumption isn't valid.
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