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Technology Stocks : Advanced Micro Devices - Moderated (AMD)
AMD 213.43+6.2%Dec 19 9:30 AM EST
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To: milo_morai who wrote (80369)5/21/2002 2:26:43 PM
From: THE WATSONYOUTHRead Replies (2) of 275872
 
P = CfV^2

where C= Capacitance, f = frequency and V = voltage. Since power elevates with the square of the voltage, a small bump in voltage has a big impact on power.

By frequency increases alone, according to this formula a 3.4GHz Northwood will consume 1.7 times (3.4/2) more power than a 2GHz Northwood. If voltage is increased, and judging from the voltage hikes necessary in Willamette ramping as well as Northwood overclocking reports, it appears very likely that the voltage will have to be raised, probably even before getting to 2.8GHz.

If frequency is increased by channel length reduction alone, then gate (maybe 1/2 of total capacitance) capacitance is decreased. So the power levels will only marginally increase with frequency until the channel length
reaches the point where the Vt starts to rapidly drop with any further reduction of channel length. This is the kink in the Vt vs. channel length curve which indicates that the device design is maxed out. I'll say again.... my guess is that Intel reaches that point at 3GHz and only with a partial shrink (10% all ready in place) and possibly also with a Vcc tweak to 1.55V. I think this occurs at around 75W and I don't think they will achieve large volumes there. My guess is that they are still on a absolute balls to the wall mad dash to 90nm to ward off AMD.

THE WATSONYOUTH
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