Advanced Micro Devices - Moderated (AMD) Message Board

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Technology Stocks : Advanced Micro Devices - Moderated (AMD)

AMD 215.00

+0.7%

Dec 22 3:59 PM EST

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To: dougSF30 who wrote (133633)	9/23/2004 7:18:15 PM
From: dougSF30	of 275872

Paul's idea on smaller die = higher die temp looks solid: aceshardware.com Yup, that's it: Smaller die = higher temperature for same power: By dougSF on Thursday, September 23, 2004 11:16 PM GMT As an approximation we've got Q = k * A * dT / d Q = rate of heat flow (W) k = conductivity constant A = junction area dT = temperature difference (between die and heatsink) d = distance of heat flow It's pretty clear you'd expect the temperature to be significantly higher for a 90nm 84mm^2 die, vs a 130nm 144mm^2 die. So much so, in fact, that I suspect the 90nm 3500+ may be dissipating significantly less power than the 130nm 3500+, because the die temperature difference is not all that large. Link: parker.com

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