Ben /Hedgefund, Re: EU Investigates QCOM- and >>>
“ we must be having a great quarter....Buy Q”
A great quarter, and more importantly the inflection point (hockey stick ramp) on the WCDMA “S” curve.
Re: “Buy Q” >>> May be some better opportunities before dust settles????
Snip >>
“Broadcom, Ericsson, NEC, Nokia, Panasonic Mobile Communications and Texas
Instruments have each filed Complaints to the European Commission
requesting that it investigate and stop Qualcomm's anti-competitive
conduct in the licensing of essential patents for 3G mobile technology.”<<<<<
Seems to me all but BRCM have signed licenses with the Q, agreeing to the terms and conditions that they now call “unfair”. In fact, some have agreed to several licenses (Subscriber eq, Infrastructure, ASICs, and Test Equipment). I rather doubt a gun was held to their heads to sign such agreements.
The ASICs licensees include both TXN and NEC and the following :
Agere Systems Inc.
EoNex Technologies, Inc.
Fujitsu Limited
Infineon Technologies AG
Koninklijke Philips Electronics N.V.
Lucent Technologies Inc.
Motorola, Inc.
NEC Corporation
Renesas Technology Corp.
Texas Instruments Incorporated
VIA Telecom, Inc
It appears that the other five named in the complaint are supporting BRCM in its US suit against the Q. Again, BRCM appears to want the same favorable terms as TXN, which were under NDA and illegally disclosed by TXN.
+.. Apparently BRCM values its patents commensurate with TI’s for cross-license purposes.
+.. It appears that this is another fallout from TXN’s illegal disclosure of those Licensing terms that apparently the Q was not able to prove it was harmed from such. One wonders if Qualcomm could now go back against TXN for those illegal disclosures?
How will the courts define “fair and reasonable” and “non-discriminatory”? Seems to me they only have to turn to the GSM licensing schemes to get an understanding of what’s been acceptable in the past (ref Korean complaints, etc). The Q’s royalty rate @ ~ 5% should appear “fair and reasonable” under such comparison. |
