Well what they probably have is 400 meters of something plunging like a pencil.
What they see from the EM is the center of the conductor which is spread electrically like it would be if you had an aerial and you were 1/2 a mile from a conductor lying on the ground. As you walked east or west and took readings of that exposed conductor. say a part of an old transmission line in this thought experiment, you would get a certain reading, but it would not tell you exactly how long the thing was, just that your signal did not fall off much in the travelled. It could be from conditions between you and the conductor, the strength of the conductor, its geometry or size. From size, conductance and distance the signal is made. (Maxwell's Field Laws) So with three variables you cannot tell exactly what all of the variables are in magnitude just from just position of reading and amplitude. It is more complex even than that, as there are some factors to decide from that are known, or probable.
They think they know from the EM what the dip is, and the plunge, what the width is, and the volume of sulphides. But it is NOT an exact science. What is probable is that it is much like the other three nearby ore bodies. About 350 feet long or maybe 500 and about 500 feet thick ( the distance at right angles to its plunge or sometimes the vertical distance from one edge of a limb to ther other) and plunging at about 60 degrees down to the west beneath the surface for anywhere from 1000 to 2000 feet or more. As you go west you pick up the plunging parts beneath you in your readings. So if you see it 1200 feet west, it is probably 1200 feet deep straight down to the top of the plunging mass -- this being the furthest west point of the anomaly.
Why does it react electrically that deep? Because you see the mass of it, which is exposed on surface on the east, as if you were right above it on the west when you take a reading.
When the aerial of the EM system is placed on the ground 1200 feet away west, it still sees the center of the body to the east and at 30 degrees plunge from the vertical. That distance is probably only 600 feet from the receiver in the easterly direction. So it appears as beneath the receiver.
So what is the probable size, best case scenario? 500 feet strike length by about 25 feet wide, by 2000 feet down plunge. That would be the best.. And I think it is half that.. so 2 point two million tons.
Maybe.
If it that size, then given the shares out, it is near fully discounted in price, but given that we know nothing yet about what will be hit, or other lenses, that could be unfair. However to prove it is as large as I said it could be, then they have to drill at least 30 holes to 50 at 250 foot spacings vertically and 120 feet horizontally.
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