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Politics : Formerly About Advanced Micro Devices

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To: kash johal who wrote (26902)12/18/1997 7:36:00 PM
From: Brian Hutcheson  Read Replies (1) of 1573921
 
Kash , re. math
it was a simple approach to get the big picture . If estimated cost of K6 on .35 was $70 (according to analysts) , then ignoring fixed costs which become less of a factor with volume production . The wafer costs are the same for .25 then the costs are proportional to the different yield between the 2 processes . That is why I used 140/380 .
BTW the total cost of 140 wafers at $70 is $9800 , divide that by 380
and you arrive at $25.78 which of course is the theoretical maximum yield . Of course someone (read Intel police) will pick holes in that
calculation , but it does give an idea of sorts .
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