SI
SI
discoversearch

We've detected that you're using an ad content blocking browser plug-in or feature. Ads provide a critical source of revenue to the continued operation of Silicon Investor.  We ask that you disable ad blocking while on Silicon Investor in the best interests of our community.  If you are not using an ad blocker but are still receiving this message, make sure your browser's tracking protection is set to the 'standard' level.
Politics : Formerly About Advanced Micro Devices

 Public ReplyPrvt ReplyMark as Last ReadFilePrevious 10Next 10PreviousNext  
To: Petz who wrote (31387)4/8/1998 1:58:00 AM
From: Maxwell  Read Replies (1) of 1571462
 
John:

Let's do some simple arithematic

# of possible dice/8" wafer
350 dice/wfr for 0.25um K6
293 dice/wfr for 0.25um K6-3D (ratio of 68mm^2/81mm^2)
FOR K6
Wafer Out 30% Yield 40% Yield 50% Yield 60% Yield 70% Yield
(per week) 105 d/wfr 140 d/wfr 175 d/wfr 210 d/wfr 245 d/wfr

3000 wfrs 315000 420000 525000 630000 735000
( 1 WEEK OF PRODUCTION)

3780000 5040000 6300000 7560000 8820000
(12 WEEKS OF PRODUCTION)

4000 wfrs 420000 560000 700000 840000 980000
( 1 WEEK OF PRODUCTION)

5040000 6720000 8400000 10080000 11760000
( 12 WEEKS OF PRODUCTION)

K6-3D
Wafer Out 30% Yield 40% Yield 50% Yield 60% Yield 70% Yield
(per week) 88 117 147 176 205

3000wfrs 263700 351600 439500 527400 615300
( 1 WEEK OF PRODUCTION)

3164400 4219200 5274000 6328800 7383600
( 12 WEEKS OF PRODUCTION)

4000wfrs 351600 468800 586000 703200 820400 ( 1 WEEK OF PRODUCTION)

4219200 5625600 7032000 8438400 9844800
( 12 WEEKS OF PRODUCTION)

Everything depends on yield. At 50% yield AMD FAB25 should make alot of K6.

Maxwell
Report TOU ViolationShare This Post
 Public ReplyPrvt ReplyMark as Last ReadFilePrevious 10Next 10PreviousNext