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Technology Stocks : Winstar Comm. (WCII)

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To: SteveG who wrote (10012)1/16/1999 9:13:00 PM
From: wonk  Read Replies (1) of 12468
 
Steve:

The conservative limits of 38 GHz is a 1.5 mile radius? 28 GHz =2.5 miles? and 24 GHz = 3? In the loss of reach in higher freq's, how exactly is the equivalencies that you've previously discussed realized?

The only way to answer your question is to specify 1) the modulation 2) the total path loss that the link must tolerate 3) a grade of service.

Presuming the following:

1. QPSK modulation
2. Point to multipoint (90 degree sector antennas at hub) — (to Bernard's point, I have presumed that the antennas scale down as frequency increases, i.e., all frequency bands have the same antenna gain)
3. 99.999% availability (5.3 minutes per year outage due to rain)

the three frequency bands look something like this for the best and worst rain regions in the continental US;

28 GHz

.49 to 1.3 miles

for 38 GHz

.42 to 1.0 miles

for 24 GHz

.57 to 1.5 miles

If you drop down to 99.9% availability (536 minutes or about 8.75 hours) 38 GHz performance looks like this:

1.0 to 4.0 miles

Also, if one presumes point-to-point (add about 20 dB to the tolerable path loss), 38 GHz looks like this:

99.999%
.65 to 1.8 miles

99.9%
2.15 to 9.8 miles

My calculations do not have all the "bell's and whistles" which should be there for total accuracy but the general ratios should be right given the above parameters.

ww
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