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Strategies & Market Trends : TA-Quotes Plus
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To: Bill Lanius who wrote (8674)2/15/1999 1:02:00 PM
From: unixgeek  Read Replies (2) of 11149
 
I want to find an occurrence of the positive directional
movement(PDM) crossing from below the MDM to above on any day
within the last five days.

There are probably many ways (and I'm sure you'll get many responses)
but here's one possible way.

// I haven't checked this for syntactic correctness,
// but you should get the idea.

integer crossed;
crossed := 0;

integer day;
for day = -4 to 0 step 1 do
if (pdm(day - 1) < mdm(day - 1) and pdm(day) > mdm(day)) then
crossed := 1;
endif;
next day;

if (crossed = 1 and <any other conditions>) then
println symbol;
endif;
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