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Technology Stocks : LAST MILE TECHNOLOGIES - Let's Discuss Them Here -- Ignore unavailable to you. Want to Upgrade?

To: Dennis O'Bell who wrote (6454)	2/19/2000 12:02:00 AM
From: Scott C. Lemon	Read Replies (1) \| Respond to of 12823

Hello Dennis, Thanks for the pointers ... I'll have to do some reading ... > One assumes an isotropic source of power at the center of > a sphere, so the power density per unit area will be the > reciprocal of the surface area of the sphere. > > power density = (transmitter power)/(area of sphere of radius R) > power density = (transmitter power)/(4 pi R^2) I knew this one ... remember it from school ... ;-) > Next, one assumes an isotropic receiving antenna which > has an effective aperture depending on wavelength > > aperture area = wavelength^2/(4 pi) This one I need to think about ... ;-) > Just take the product and express the ratio in decibels > > 10 log (1/(4 pi)^2 * ((0.186 / f)/R)^2) > 20 log (.186/(4 pi)) - 20 log (f) - 20 log (R) This one it going to take a while ... ;-) Thanks again ... it's kinda cool to get back into the math and calculations on this stuff ... I haven't looked at the technical aspects on it in a long time ... got to caught up in the "digital" world ... ;-) Scott C. Lemon