SI
SI
discoversearch

We've detected that you're using an ad content blocking browser plug-in or feature. Ads provide a critical source of revenue to the continued operation of Silicon Investor.  We ask that you disable ad blocking while on Silicon Investor in the best interests of our community.  If you are not using an ad blocker but are still receiving this message, make sure your browser's tracking protection is set to the 'standard' level.
Technology Stocks : Advanced Micro Devices - Moderated (AMD) -- Ignore unavailable to you. Want to Upgrade?


To: Daniel Schuh who wrote (21466)12/4/2000 3:36:14 PM
From: Ali ChenRead Replies (2) | Respond to of 275872
 
Dan, <But how do you get from 0.835 w/cm-C at 25 degrees C (that from Handbook of Chem. &Phys, also approximately Pete's #) to 148 W/m-K 300 degrees K?>

Assume a cube of silicon 1cm x 1cm x 1cm, insulated
around 4 sides, with temperature difference of 1C=1K
across. Then the power through the 1cm2 area would be:

P = k[m,K,W]*0.01m*0.01m*1K/0.01m = k[m,K,W]*0.01.

If we express the same equation in centimeters,

P = k[cm,C,W]*1cm *1cm*1K/1cm = k[cm,C,W]

Both expressions represent the same value of
power. Therefore k[m]/100 = k[cm].

CRC probably quotes some pre-historical research
paper with who-knows crystal quality and orientation.
So 0.8 of CRC is pretty close to 148/100 = 1.48 of
your link.