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To: dale_laroy who wrote (44310)	6/14/2001 1:37:32 PM
From: ptanner	Read Replies (2) \| Respond to of 275872

OK, now that the K6-2 is set at 81mm^2<g> and assuming that all CPUs have the same yield except as adjusted by the square of the relative die size (per Dan3 method): Then Dan3 adjusted output capacity for Fab25 is reduced from 6.3M K6-2 to about 2.6M Durons and T-Birds (2/3 and 1/3 of total) based on die sized of 81, 103, 120 mm^2. Oh, and for Dresden with T-Bird and Palominos the yield/wafer would be reduced by about 18%. This would be a reason to continue T-Birds instead of Palominos! Dan3 should check my calculations - but I wonder if the square of die size for yield is appropriate or if it should be a something closer to the actual die size. I might be double counting the yield ratio since my analysis also include a step which estimates the #dies/wafer including edge losses. EDIT: Adjusted values taking out my likely erroneous double counting of die size results in 2.9M for Fab25 and a 12% lower die/wafer for Palominos over T-Birds. -PT