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Technology Stocks : The *NEW* Frank Coluccio Technology Forum -- Ignore unavailable to you. Want to Upgrade?

To: Frank A. Coluccio who wrote (3404)	7/22/2001 1:03:19 AM
From: ahhaha	Read Replies (1) \| Respond to of 46821

At the limit where rings achieve the same reliability they are topologically equivalent to a mesh, but at orders higher in cost to create. A complete closed mesh contains every possible ring as a subset. It is the market which by profitability discovers "the logical and physical domains of connectivity", not standards boards.

To: Frank A. Coluccio who wrote (3404)	7/22/2001 10:01:50 AM
From: GraceZ	Read Replies (2) \| Respond to of 46821

I have one question about that diagram showing a single or dual break on a fiber optic ring in the Cisco paper. It shows a break between nodes A and B. I understand how it would reroute from A to B going in the opposite direction, but how does it reroute at the break? The diagram shows the reroute between A and B. It seems to me unless there is some equipment they aren't showing on the diagram that any connections between A and B would be cut off. Do the connections into the ring provide the turnaround points? Living in a city which employs both a grid (city blocks) and a ring (the Beltway) for automotive traffic I have to tell you I'm well aware of the advantages and limitations of both. Of course, time is much more of a real factor in auto traffic so the analogy might be flawed. If I had to travel the entire distance in the reverse direction in the event of a major break in the Beltway (something that happens quite frequently sadly enough) I think I'd rather park the car and walk home.