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Gold/Mining/Energy : Gold Price Monitor -- Ignore unavailable to you. Want to Upgrade?

To: Karl Siemens who wrote (81025)	1/23/2002 5:24:02 PM
From: E. Charters	Read Replies (1) \| Respond to of 116762

If composed of gold of 14.5 specific gravity, a gold nugget of 2000 ounces need only be 16.3 by 8 inches wide inches by 2 inches thick. At 50% quartz and ten% silver by volume, SG drops to 10.4. At this SG, 2000 ounces (ounces Troy, of total sample weight of all constituents) has a volume of 2000 X 31.103= 62206 grams or 5,891 Cubic centimetes at that SG (62206/10.4). This would make a cube of 18.147 CM. per side, or 7.14 inches. This would be 364 square in. At 3 inches thick, It could be 8 inches wide by 15 inches long. ********* one scenario ** Lets say the "nugget" is 25% gold by eye. And that gold is 15 % silver, which is common in Ontario mines. That gold is therefore 18.6 specific gravity. Let's say someone has calculated its weight in gold alone, not including quartz, to be 2000 ounces. The volume of gold at that SG to be that weight is 3,344.4 CC's. So its total volume would be 4 times that or 13,377 CC's. Or 23.73 CC's cubic or 9.34 (on a side) inches cubic. (Total volume is 815 cu inches.) At 4 inches thick it is 203.98 square inches or let's say 20.39 inches by ten inches wide. I have not seen it, but that is what one could estimate given the hypothetical figures. EC<:-}