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Pastimes : Clown-Free Zone... sorry, no clowns allowed -- Ignore unavailable to you. Want to Upgrade?

To: Secret_Agent_Man who wrote (148056)	2/3/2002 1:25:26 AM
From: Petrol	Respond to of 436258

<<<The matrix P has three eigenvalues: one is equal to 1 and the modulus of the other two is smaller than 1. The eigenvector corresponding to eigenvaue 1 is the stationary probability distribution, i.e., its components are the probability of Y(t)=0,1, and 2 for t very large. We are interested on the probability of Y(t)=0, which reads, for e small: P0= 5/13 - (440/2197) e = 0.3846 - 0.2003 e which is the probability of using the bad coin 3. The probability of winning is: pwin= (1-P0) (3/4-e) + P0 (1/10 - e) = 1/2 - 147/169 e = 0.5 - 0.87 e which is smaller than 0.5 for e positive.>>> One day I'll spend some quality time looking at this...but for now, it might as well be swahili. ggg Thank you for the link!