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To: ptanner who wrote (73630)3/6/2002 12:53:13 AM
From: PetzRead Replies (1) | Respond to of 275872
 
re:Using the picture here: chip-architect.com.

and a die area of 145mm^2 results in an estimated 17mm^2 for the L2

EDIT - did you count both chunks of L2?

WOW, that is really, really small. 512K has got to be at least 6*8*512K transistors, or about 25M transistors. Probably more like 30M, because I believe Intel also uses ECC.

If AMD can build it's L2 with the same density as Intel, a 1M L2 would only require 34mm. Even if we increase that to 40mm, that leaves 64mm^2 for the core at 0.13u.

That is more than enough room, IMO, because a Duron minus the tiny L2 is, what, about 90mm^2. Going to 0.13 should reduce that to about 50mm^2, leaving 14mm for x64 and HT linkes.

Petz