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To: Windsock who wrote (168894)7/31/2002 1:07:46 PM
From: Yousef  Read Replies (2) | Respond to of 186894
 
Windsock,

Re: "This is really interesting. I guess the voltage at the source is the same as the
voltage after passing through a resistor. Voila, no voltage drop with a load."

Your analogy is correct as long as no current is being drawn (no load).
With a load, current will be drawn and there will be a voltage drop across
the resistor. Thus the voltage measured across the load would NOT be the
same as the source voltage ... I hate to break the "news" to Dan3, but there is
heat flow in his "closed box world". <ggg>

Make It So,
Yousef



To: Windsock who wrote (168894)7/31/2002 2:37:56 PM
From: Dan3  Read Replies (2) | Respond to of 186894
 
Re: I guess the voltage at the source is the same as the voltage after passing through a resistor. Voila, no voltage drop with a load

...with the difference in energy dissipated as heat.

LOL!!!

But this is a discussion of heat transfer, and unless you're going to argue that some of the thermal energy is converted by the case into a different form (are you claiming that the P4 chips do run hot enough to glow brightly...) then there is no difference in the thermal energy of the case and the die.

Any brightly glowing, red hot or white hot, P4's would be converting some of the thermal energy into visible and UV, I suppose. Or are you revealing that P4s run hot enough to generate X-Rays? That would really get rid of some energy...

:-)

PS - given this new data you've provided us with, shouldn't Intel be advising P4 owners to wear lead underwear?

CAUTION! P4 USERS ARE ADVISED THAT LONG TERM USE CAN RESULT IN CANCER, STERILITY, AND DEATH DUE TO EMISSIONS PRODUCED BY THE CPU CASE AS IT CONVERTS HEAT INTO XRAYS.

LOL!!!