SI
SI
discoversearch

We've detected that you're using an ad content blocking browser plug-in or feature. Ads provide a critical source of revenue to the continued operation of Silicon Investor.  We ask that you disable ad blocking while on Silicon Investor in the best interests of our community.  If you are not using an ad blocker but are still receiving this message, make sure your browser's tracking protection is set to the 'standard' level.
Gold/Mining/Energy : Gold and Silver Juniors, Mid-tiers and Producers -- Ignore unavailable to you. Want to Upgrade?


To: onepath who wrote (65615)6/6/2009 12:06:25 AM
From: Rocket Red  Respond to of 78410
 
okay we see on june 15 then what the real scoop is



To: onepath who wrote (65615)6/6/2009 11:01:43 AM
From: tyc:>  Read Replies (2) | Respond to of 78410
 
Sharing due-diligence.

Note that while Mt Milligan has already been subjected to a feasibility study, Berg has not; it has simply declared the extent of its resource. "Contained Metals 3.3 Billion lbs Copper, 412 Million lbs Molybdenum, 61 Million ozs Silver"

How does Berg compare with Mt Milligan ? Mt Millgan will produce 1.6 billion lbs of copper from the outlined pit. Berg boasts a total resource of 3.3 billion lbs of copper. How would Berg's Moly and Silver compare with MtM's gold ?

Assume a "normal" gold price is $950 per oz and "normal" moly price is $10 per lb, then 95lbs of moly equals 1 oz of gold. Berg has 412 million lbs of Mo, thus the equivalent of 4.33 million oz of gold.

But Berg has also 61 million oz of silver. Assume a price ratio of 60:1, and that silver is the equal of another million oz of gold. So Berg's MO and silver might be equivalent to 5.33 M oz of gold.

Mt Milligan boasts of more than 6 million oz of gold although only 4.6 M oz is recoverable within the proposed pit outline. If we reduce Berg's 5.33 M oz gold equivalent by the same ratio, recoverable by product metals might have a gold equivalence of (4.6/6*5.33=) 4.1 million oz.