To: Petz who wrote (27679 ) 1/5/1998 10:26:00 PM From: Yousef Read Replies (1) | Respond to of 1572893
John, Re: "If you follow this thread back to where it started, increasing Vcc is exactly what I was talking about ..." John, I followed the thread back ... and what started this discussion was your incorrect statement: "Since power consumption generally increases as the square of frequency" Remember, Power ~ CV^2f ... C=Capacitance, V=Voltage, f=Frequency The correct statement is if you increase voltage AND frequency then the power will scale as V^2f (more than just the square of the voltage). Re: "AMD's 0.25 generation has apparently physically shrunk the FET by more than the expected (0.25/0.35)^2 ratio, judging by the die size. This is why I believe AMD will catch up to Intel on CPU speed instead of being 2 speed grades behind." This statement is very false ... AND needs to be corrected immediately!! The fact that AMD has a more dense process does not mean the AMD FET's are "smaller" than the Intel FET's. The size of the FET (electrical gate length) and gate oxide thickness are limited by the oprerating supply voltage. Thus, Intel actually has smaller FET's that give the same drive current (Idsat) as the larger AMD FET's. The reason that the AMD process produces smaller die is due to tighter design rules (spacings between poly lines and contacts, contact enclosures ...). These design rules only affect density and not FET size/performance. Your assertion that performance is affected is totally wrong ... and misleading. BTW, AMD's .25um process is optimized for 2.2V supply voltages (as reported in the literature). As AMD lowers the supply voltage down to 1.8V for mobile notebooks, the performance will fall of very quickly. Notebook K6's in .25um process at 1.8V will not be running at 300mhz. They will be lucky to hit 233mhz. Make It So, Yousef