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To: Johan Van Houtven who wrote (5351)	7/11/1998 4:11:00 PM
From: Bob Jagow	Read Replies (1) \| Respond to of 11149

Johan, Help shows your problem -Bob ------------------------------------- Max( StartDay , EndDay , Item ) Returns the maximum value of an item for a range of dates. StartDay must be <= 0 EndDay must be <= StartDay Item must be a valid item token. Example: output="myfile"; if ( Close(0) >max(-1,-250,cl) then println symbol; endif; In this example, Max( -1,-250,cl ) returns the highest closing price for last 250 day period.

To: Johan Van Houtven who wrote (5351)	7/11/1998 4:50:00 PM
From: Bob Jagow	Respond to of 11149

Sorry, Jan, I missed your point. Max(0 -daysloaded +1, hi) works fine; the problem is indeed a parse-time bug like Brooke and I found for the recent slope scan. (Where I had to add a positive # aa a kludge in post #5268 b:= .0001+(num/den); kludge.) You can see this with -------------------------------------- //JVH stock data Scan by JVH output = "jvh-stocks-out.lst"; Float EMA17, EMA50, EMA200; Integer NumDays; DaysToLoad = 300; daysRequired = 250; //always good idea to avoid bounds stop NumDays:=-.5*(DaysLoaded-1); Println DaysLoaded,",", NumDays, ",", Max(0, -1 + NumDays ,hi); ------------------------------- where this -1 tricked the parser into accepting Numdays. Bob