To: john griffin who wrote (1496 ) 7/20/1998 4:17:00 PM From: RAY BARBER Read Replies (1) | Respond to
John, I guess maybe my math could be wrong, but I really don't think so. Since each cylinder in the OXTWO engine fires twice per revolution, then each piston must travel through the bore eight times, four times up and four times down. If you multiply the number of cylinders (eight) times the number of strokes per cylinder (eight), the total amount of strokes per revolution is sixty-four. In a conventional four stroke engine, each piston only travels through the bore twice per revolution, once up and once down, so it takes two complete revolutions of the engine to complete the four stroke sequence for each cylinder. In a conventional engine the number of strokes per revolution is sixteen, (two strokes per cylinder times eight cylinders) and the OXTWO has sixty-four strokes per revolution. Factors don't really enter into this discussion in my view. The piston speed is not constant in either engine, since both have to stop and start when they change directions. The average piston speed is what we are referring to in our discussion. Due to the design of the OXTWO the internal cam of the engine could cause the piston to remain fully extended or fully retracted for extended periods of time. If this were true, then the terminal piston speed would be more than four times greater in the bore than in a conventional four stroke engine.
