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To: jhild who wrote (1381)	8/8/1998 5:19:00 PM
From: E. Charters	Read Replies (1) \| Respond to of 2770

If you pass a date back to the program, the variable is still fixed. How does it calculates the time differential? If a COBOL program has a date routine that subtracts 1960 from 2004 you are going to tell me that simply passing the answer to the program is it? So your code will intercept the section that does the subtraction and send the code the real answer? And how will it store the data after it gets it.. are you going to change the pic section of the code that does the two digit store and what about the pic section that formats the two digit entry? and all the fortran formatting.? You may be able to fool a non programmer that you can do it at the operating system level but you have intercept variables that are in machine code that the OS cannot have any knowledge of. A simple subtraction would not be detectable as having anything to do with a date. It would not be known to your chip as a date transaction and the interruption of the routine at any rate may crash the machine. All data passing to the program has to be typed and formatted. If you send back an amount that is wrong and it disagrees with another calc that is not trapped.. then you have an error EC<:-}