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To: Andrew H who wrote (78)	11/12/1998 11:22:00 PM
From: CYBERKEN	Read Replies (1) \| Respond to of 317

Hate to be a wet blanket here, but the Aquafuel technology sounds like a stroke of genius. Cheap, simple, so obvious it should have been thought of long ago. In other words: Far too good to be true. No, I'm not the irresponsible type that will call this a scam casually without giving it any real thought. We've seen that around,lately. (:->) I'm just saying that a situation like this cries out for VALIDATION through a partnership with a well-positioned deep-pockets energy company. The evident non-pursuit of such a partnership makes me skeptical for the time being, but I will continue to watch.

To: Andrew H who wrote (78)	11/17/1998 3:13:00 PM
From: Howard Williams	Read Replies (2) \| Respond to of 317

Science???? Credibility problem here.... Andy, Mr. Clancy sent the following to you... >>>3. Because there is no electrolyte or other "resistor" used in the water, the electric arc passes through with no loss in power. Now draw a picture of a city and then draw a picture of a power plant which provides electricity to that city. Draw a line connecting the two and assume that line is the power line going from the plant to the city. Directly in between these two items, insert an AquaFuel apparatus. The power that leaves the plant then passes through the AquaFuel apparatus. As the "arc" finds no resistance when passing through the AquaFuel apparatus, there is no loss in power so the city will still receive 100% of the power sent not accounting for normal loss that occurs in such a transmission. However, the act of "passing through" the AquaFuel apparatus creates AquaFuel. This is a crude picture but it makes the point that AquaFuel can be inserted in an existing power stream without taking away from that power output. In this scenario, you are utilizing an existing flow of power so theoretically, there is no cost to produce AquaFuel.<<< Facts: 1) you cannot create an arc (a hot thing, something that takes power to generate, like heating the filament in a light bulb) without using power! Remember, this stuff is generated at 5000 degrees (their info) 2) if there was no electrolyte or other resistor in the water, it'd be a perfect insulator and would not transmit the current. If it was a superconducting liquid (not) it would transmit the current with no power loss. 3) stating that the power passes through and generates AquaFuel with just normal transmission losses is akin to saying they get something for nothing. 4) the AquaFuel apparatus doubtless produces combustible gases. No question. Just the reverse of a fuel cell that takes oxygen and hydrogen and produces electricity and water. Their "crude" welder demo is probably a good demo. It takes x amount of power to make y amount of gas. 5) the bottom line question that they haven't answered anywhere is how much energy input is required to get fuel containing how much energy (when burned) out. JMHO as a retired physicist, H.W.