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Gold/Mining/Energy : Winspear Resources -- Ignore unavailable to you. Want to Upgrade?

To: teevee who wrote (9688)	11/24/1998 6:39:00 PM
From: wayne cath	Read Replies (1) \| Respond to of 26850

Why do two of my most favorite and knowledgeable posters have to allow an exciting debate to deteriorate into such emotional name calling? You guys are both a great asset here......... please stay wayne

To: teevee who wrote (9688)	11/25/1998 10:25:00 AM
From: gg cox	Read Replies (1) \| Respond to of 26850

No,here are your ridiculous numbers you do the math! To: Steve Joy (9073 ) From: teevee Monday, Nov 2 1998 11:54PM ET Reply # of 9695 Hi Steve, I took the liberty to do the math for you. Assume a radius of say 2.5 kilometers and to keep it simple and conservative, assume the cone is flat. So:(2500meters)x(2500meters)x(3.14[pi])x(2.6meters average thickness)x(3 tonnes per cubic meter [rock density])/2=76,537,500 tonnes potential tonnage in one semi-circular cone sheet. IMO there are two and maybe three semi-circular cone sheets. Don't worry, I put new batteries in my calculator. regards Slap in some new Duracells and try it again remember "IMO there are two and maybe three semi-circular cone sheets." gg (cretin)