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To: George T. Santamaria who wrote (170)	1/25/1999 6:34:00 PM
From: Frank A. Coluccio	Read Replies (2) \| Respond to of 626

I think that we're all waiting to hear what the technology is that can support those modulation rates, George. I don't have the answers, and I recall posting similar questions in a round 'bout way, myself, upstream. Some of these manufacturers have stated that they will have product out in the next couple of months. They will need to make more illuminating disclosures re how they work, if they are to be accepted by the user community. Some may differ with this view, since they believe that the company(ies) may have a legitimate reason for wanting to protect their intellectual property and patents, pending or otherwise, until some later date. You are correct though, in that this is a place for airing new ideas, and spreading some information around, and seeking same, regarding new developments in the opticals used for communications. In fact, you, yourself, have just added to that legacy by posting your message here, which was very well done. Thanks. Regards, Frank Coluccio

To: George T. Santamaria who wrote (170)	1/27/1999 12:47:00 AM
From: Webster Groves	Read Replies (1) \| Respond to of 626

<<. If the 200 GBit data rate were a single serial data stream, the wavelength would be 3 x 10^10 cm/sec / 2x10^11/sec = 0.15mm (0.006"). It would take a very small microelectronic structure just to transmit and manipulate the signal for modulation.>> I took this problem to work and our Thinking Machines supercomputer came up with the answer that 3x102/2x1011 = 0.15 cm (not mm), so things are not so bad. By the way the correct answer to your preface (I believe) is ""mm-wave mixers"; they are commercially available from a few sources. <<To me DWDM has one advantage in that I can conceptually agree with combining a number of streams at 2.5GB ( as electrical signals they are: 3 x 10^10 cm/sec / 2.5x10^9 /sec = 25mm wavelength) optically because the technology for modulation is fathomable.>> Once again the TM computer says answer is ......12 cm (not 25 mm = 2.5 cm). I once had problems like this when using an HP calculator with donut sugar in the keyboard. Try using a supercomputer; they don't allow donuts in the computer room. Now back to very infrequent lurking....... -wg Sorry to appear flippant, but that's me - no offense intended.