To: Larry Levine who wrote (4837 ) 3/17/1999 8:44:00 AM From: Rob29 Read Replies (2) | Respond to of 5300
Larry, You are asking good questions and they are certainly welcome on this board. (I don't mind negative statements backed by reason or serious questions ... they belong here). I agree the numbers can be confusing. Lets step through it. (Single Word Search) Search on Voice yields 5074 Internet 163 Graphics 8 CD-ROM (Single Word Search) Search on Recognition yields 1345 Internet 52 Graphics 10 CD-ROM (AND Search) Search on Voice & Recognition yields 1607 Internet 16 Graphics 6 CD-ROM (OR Search) Search on Voice | Recognition yields 6419 Internet 215 Graphics 18 CD-ROM (Phrase Search) Search on Voice Recognition or "Voice Recognition" yields or 72 Internet 2 Graphics Notice the AND search results in 1607 hits in Internet while the individual searches result in 5074 and 1345. At first glance this is confusing because you would expect the AND result to have 1345 hits or less since this is the number of hits on 'Recognition'. However, we are working at a web page level and Spyhop counts each matching word on the page as a hit. In this case the word 'Voice' appears multiple times on the same page that contains the word 'Recognition'. Lets do a smaller example. Given the following 4 sample web pages 1) Voice, Voice, Voice, Recognition. 2) Voice Recognition. 3) Voice 4) Recognition. A search on Voice would yield 5 hits (from sample pages 1,2,3). A search on Recognition would yield 3 hits (from sample pages 1,2,4). A search on Voice & Recognition would yield 6 (from sample pages 1,2). A search on Voice | Recognition would yield 8 (all sample pages). A search on "Voice Recognition" would yield 1 (from sample pages 2). Remember the & means only consider web pages containing both words (in this example web pages 1 & 2). After narrowing the search to these web pages all hits are counted. Hope this helps ... if you think this will be an issue for users in the production version then please send it as feedback to WordCruncher (email feedback@spyhop.com) Regards, Rob