Can you duplisim gravity by spinning a circle space station and walking around the inner rim? What happens when you jump up, or in-center?
In order to gravitate the mass, it has to be impelled cirumferentially attachable. If in weightless space, it cannot be so impelled, as it is not stuck to anything. If weightless within a rotating curved tunnel, eventually, you hit the outerwall, and then you are impelled by it centrally, and gravity is simdupled. Or so it seems.
But if you jump inwards, there is no gravity and you just hang there except you are travelling at rim speed at a smaller circumference, so the rim gradually comes back to you, giving the impression of falling. In a space station 100 feet in radius A=V^2/R 3200=V^2 V=56.56 fps. If you jump up 3 feet exactly, you will return to the rim in 14.06 degrees. (inverse cosine of 97/100.) or in .433 seconds. Falling on earth it takes S=1/2at^2 3=16t^2 T=sqroot(3/16) or .433 seconds. So it is the same.
To jump up to 3 feet is a bit different in space, as you need a lower lift off speed as your speed never stops, as there is no deceleration of gravity. You only lift off with 6.92 fps or you overshoot. You "land" with a tangential component vector combined, a bit greater than rim speed if you run in the direction of the spin. |
