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To: Scott C. Lemon who wrote (6450)2/18/2000 9:40:00 PM
From: Dennis O'Bell  Read Replies (1) | Respond to of 12823
 
Hi Scott...

The calculation he cites is in any book on communications
engineering or antenna handbook.

One assumes an isotropic source of power at the center of
a sphere, so the power density per unit area will be the
reciprocal of the surface area of the sphere.

power density = (transmitter power)/(area of sphere of radius R)
power density = (transmitter power)/(4 pi R^2)

Next, one assumes an isotropic receiving antenna which
has an effective aperture depending on wavelength

aperture area = wavelength^2/(4 pi)

Just take the product and express the ratio in decibels

10 log (1/(4 pi)^2 * ((0.186 / f)/R)^2)
20 log (.186/(4 pi)) - 20 log (f) - 20 log (R)

the .186 is from speed of light in miles/microsecond

Et voila...

To take account of antenna gains, be sure they are relative to
an isotropic antenna - the usual theoretical benchmark that is unrealizable in practice but simplifies formulas.