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Politics : PRESIDENT GEORGE W. BUSH -- Ignore unavailable to you. Want to Upgrade?

To: J_F_Shepard who wrote (214074)	1/2/2002 4:18:08 PM
From: George Coyne	Read Replies (1) \| Respond to of 769670

Yes, each flip is independent, but the chances of 10 independent flips in a row all ending up heads is 1/1024. My last post on the subject. Remain ignorant if you like.

To: J_F_Shepard who wrote (214074)	1/2/2002 4:25:42 PM
From: Neocon	Read Replies (1) \| Respond to of 769670

George is correct about the probability of 10 in a row, although each flip has a probability of 50%: Probability of Simple and Compound Events A simple illustration of probability is given by the experiment of tossing a coin. The sample space consists of one of two outcomes-heads or tails. For a perfectly symmetrical coin, the likely assignment would be 1/2 for heads, 1/2 for tails. The probability measure of an event is sometimes defined as the ratio of the number of outcomes. Thus if weather records for July 1 over a period of 40 years show that the sun shone 32 out of 40 times on July 1, then one might assign a probability measure of 32/40 to the event that the sun shines on July 1. Probability computed in this way is the basis of insurance calculations. If, out of a certain group of 1,000 persons who were 25 years old in 1900, 150 of them lived to be 65, then the ratio 150/1,000 is assigned as the probability that a 25-year-old person will live to be 65 (the probability of such a person's not living to be 65 is 850/1,000, since the sum of these two measures must be 1). Such a probability statement is of course true only for a group of people very similar to the original group. However, by basing such life-expectation figures on very large groups of people and by constantly revising the figures as new data are obtained, values can be found that will be valid for most large groups of people and under most conditions of life. In addition to the probability of simple events, probabilities of compound events can be computed. If, for example, A and B represent two independent events, the probability that both A and B will occur is given by the product of their separate probabilities. The probability that either of the two events A and B will occur is given by the sum of their separate probabilities minus the probability that they will both occur. Thus if the probability that a certain man will live to be 70 is 0.5, and the probability that his wife will live to be 70 is 0.6, the probability that they will both live to be 70 is 0.5×0.6=0.3, and the probability that either the man or his wife will reach 70 is 0.5+0.6−0.3=0.8. encyclopedia.com

To: J_F_Shepard who wrote (214074)	1/2/2002 4:52:01 PM
From: Bob	Respond to of 769670

A better way to explain the coin flip argument is just go with two or three flips. With two flips, all possible outcomes are HH TT HT TH. Any one of these has a 1 in four chance.(25%) So 1/2 X 1/2 = 1/4 = 25% With three flips the outcomes are HHH TTT HHT TTH HTH THT HTT THH. Any outcome would have a 1 in 8 chance, or 12.5%, which is arrived at by multiplying 1/2 X 1/2 X 1/2. Of course each random flip is 1 out of two, but that's not what is being asked. it's the odds of 10 consecutive heads or tails.I don't feel like listing all 1024.<gg> Regards, BobP