To: Steven Bowen who wrote (798 ) 12/31/1997 2:25:00 PM From: Bernard Levy Read Replies (1) | Respond to of 2063
Here is a rough answer to your question. For line of sight communication, the power attenuation between the transmitter and receiver is proportional to the square distance between the transmitter and receiver and to the square of the transmission frequency. Because TGNT operates at 24GHz and WCII at 38GHZ, the attenuation is therefore (1.5)^2 greater for the WCII channel. This means that for identical channels, WCII would need to have cells with a radius 66% smaller than TGNT. To compensate for the larger attenuation at higher frequencies, the FCC has made the bandwidth per license larger at 38Ghz (100MHZ) than at 24GHz (80 MHz). How the larger bandwidth is exploited depends on the choice of modulation format, but for wideband FM (the simplest case of all) the signal to noise ratio gain at the receiver output (with respect to the receiver input) is proportional to the square of the channel bandwidth. In other words, the wider the bandwidth, the easier it is to reject the noise. For FM, this would give a (1.25)^2 gain advantage to the 100MHZ licenses of WCII versus the 80MHz licenses of TGNT. However, this is a very rough analysis. I suspect that TGNT and WCII must be using a digital modulaton technique, such as QPSK. Then the wider bandwidth can be exploited by applying some form of forward error correction. The analysis becomes compicated. The bottom line is that the FCC is less incompetent than it may appear. They have obviously equalized the licenses to take into account the spectrum location. Going back to CVUS, because its license is at 28GHz, a 100MHZ channel for WCII must be equivalent to a 85MHz channel for CVUS, so the 1.15GHz CVUS bandwidth would give them approximately 13 channels (instead of 11.5 in the earlier estimate by Brian Coakley).