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Technology Stocks : Advanced Engine Technologies (AENG) -- Ignore unavailable to you. Want to Upgrade?


To: Greg Cummings who wrote (218)5/20/1998 2:02:00 PM
From: M Murphey  Read Replies (1) | Respond to of 3383
 
Real Time update 13:56

Last @ 21 (-5 87/100)
Bid 20.25
Ask: 21 1/4

FYI,
MM



To: Greg Cummings who wrote (218)5/20/1998 2:53:00 PM
From: Sword  Read Replies (2) | Respond to of 3383
 
There is a problem unique to this engine that does not exist in conventional internal combustion engines -- that of significant gyroscopic forces:

Suppose the inside diameter of the rotating mass is 12 inches. At 1250 RPM the total angular momentum will be:

Angular momentum (H) = Mass moment of inertia (I) times angular velocity of the engine (omega)

The perpendicular torque (T) created by the gyroscopic effect when you turn the car will be:

T = H times turning rate of the car (zeta)

Suppose you turn the steering wheel of the car to make a turn and you take 1 second to turn the steering wheel 90 degrees. The car will alter its trajectory by about 20 degrees. Therefore the turning velocity will be 20 degrees per second.

The mass of the engine is 140 lbs. Suppose that 2/3s of the mass is rotating mass or about 90 lbs. Suppose the mass is evenly distributed throughout the volume of a 12 inch by 11 inch cylinder. The mass moment of inertia will be:

I = 140 lbs times (12 inches)^2 divided by 8 = 2520 lbm-inch^2

Therefore,

H = 2520 lbm-inch^2 times 1250 rev/3600 sec = 875 lbm-inch^2-rev/sec.

Finally the torque is:

T = H times zeta = 875 lbm-inch^2-rev/sec times 20 deg/sec = 17500 ibm-inch^2-rev-deg/sec^2.

Or, simplifying the units,

17500 lbm-inch^2-rev-deg/sec^2 times (lbf-sec^2/386 in-lbm) times (2pi radians/360 deg) times (2pi radians/rev) = 1789 in-lbf.

This is the perpendicular wrenching force that would be applied by gyroscopic effects on the OX2 engine running at 1250 rpm as the vehicle enters a turn. On a 12 inch center, this would amount to 150 lbs on the walls of the engine. It will also cause the car to pitch. It will also load the bearings on the rotating cylinder inside the engine.

This will not be noticed on any dynamometer since the engine is rigidly mounted to the dyno platform. The gyroscopic effect in a standard ICE is small by comparison.

-Sword



To: Greg Cummings who wrote (218)5/29/1998 10:25:00 PM
From: John O'Neill  Respond to of 3383
 
Greg Cummings
Has Shelby had any recent comments??