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Pastimes
INTERMEDIATE ALGEBRA
An SI Board Since September 1999
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Introduction Compact
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46 Stop it, you are scaring me. Now I have to call Not Flargg. Not Flargg likes Don Pueblo-9/12/1999
45 Ah! It appears that you are also psychic. This does *not* make me feel any bettDon Pueblo-9/12/1999
44 I respectfully submit that my answer of zero is also correct, because of the prDon Pueblo-9/12/1999
43 <i>Watch out for Mr. Gold, he has a three figure IQ. </i> HAH! OnNazbuster-9/12/1999
42 Neither solution is complex? Oh, that makes me feel much better. Don Pueblo-9/12/1999
41 Correct-o-mundo, sir. Fun problem, eh? You got one? Watch out for Mr. Gold, Don Pueblo-9/12/1999
40 2Cage Rattler-9/12/1999
39 <i>Proprietary wavelet transform indicates freq 12 for amp 10. Nazbuster-9/12/1999
38 Correct! It doesn't matter how large the original sphere... to get the Nazbuster-9/12/1999
37 James, Congratulations! It was a difficult problem. When you say "neitheMechanicalMethod-9/12/1999
36 width = 12.31186, to 5 places. That's from MathCAD. Mathematica gives 2 Lazarus_Long-9/12/1999
35 Hi dmarkham! About strawberry pie feet longer should do it, I think. peterpeter michaelson-9/12/1999
34 Hedging my 12 bet with another at 12.32 feet.MechanicalMethod-9/11/1999
33 GAWD!!!!!!!!!!!! THIS IS BAD! I tried a brute force approach and ended up withLazarus_Long-9/11/1999
32 Grubbing differential index freq 33 of common cycle between ladders A and B witMechanicalMethod-9/11/1999
31 Proprietary wavelet transform indicates freq 12 for amp 10. How wide is alley MechanicalMethod-9/11/1999
30 Damn, dude. You are *good*!!! I'm bookmarking you for any bar bets I run Don Pueblo-9/10/1999
29 Ok this was fun for awhile but "They told me there would be no math" jbIII-9/10/1999
28 Then again... If on 1st weighing, ABCD vs EFGH, ABCD is heavier, Weigh ABENazbuster-9/10/1999
27 I'm glad I'm not playing you for money, dude. <G> Don Pueblo-9/10/1999
26 That's good! OK. Let's say the "left 4" are "heavier&quoDon Pueblo-9/10/1999
25 Have to go home.. will do the 2nd part over the weekend.Nazbuster-9/10/1999
24 I have 1/2 the problem worked out so far: Start with 12 balls. 1st weighinNazbuster-9/10/1999
23 So my answer could be right! You cannot guarantee that I am not correct! ThatDon Pueblo-9/10/1999
22 Rats. Maybe it *was* 12! I remember that somebody on SI put the answer on the Don Pueblo-9/10/1999
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